15 questions
CXD5602's nuttx usb function device driver is not functional enough, so I'm thinking of writing a new one.However, the CX5602 documentation did not provide any details (defining registers, behavior) a...
I'm thinking of making a program to operate USB keyboard support devices such as PC and PS4 by connecting Windows 10 and USB cable.I can find articles that will be realized on raspberry pi and Android...
If multiple cameras are connected at the same time, the camera must be differentiated.I think the ID of the only facility will distinguish which camera is connected.Do USB cameras currently have such ...
I am creating an application to receive MIDI Note ON and OFF messages on Android. I have a MIDI cable connected to the Android terminal via micro USB.Therefore, we are developing using the API of Andr...
It is said that the Spresense body and the expansion board cannot be used at the same time because they use the same line as the UART.If I use UART on the main side of the Spresense, will I not be abl...
What you want to solveI would like to connect to multiple computers and smartphones using USB dongle to use the Internet.Example)Connect the USB dongle to the PC and make the PC the master access poin...
I would like to connect the Android device to the device via USB for serial communication. (Android is the host) I searched the Android API reference and found a class called Android.hardware.usb.http...
I would like to connect the USB device (sensor) to the Raspberry Pi and use PyUSB to communicate data.The programming language is Python.Now, pyusb, libusb are already installed, but I get the followi...
We put VMware in Window 11 and use Ubuntu 20.04.1 as a virtual operating system.You are now learning about the dd command.I didn't really understand the difference from the cp command, so I came up wi...
Thank you for your help.In order to find out how many devices are connected to the PC in C#, Creating an application to view open COM ports.In order to detect a new connection or disconnect and update...
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