If there is a nested if statement like the one below, is there a good way to make it depth 1?
if(a==null){
if(b=="Ahhhhhhhhhhhhhhhhhhhh
running text
}
if(c=="good"){
running text
}
}
If there is no further action, it simply returns as follows.
if(a!=null){
return;
}
if(b=="Ahhhhhhhhhhhhhhhhhhhh
running text
}
if(c=="good"){
running text
}
If there is subsequent action, you may be able to reduce nesting of if statements by using break in do-while statements.
do{
if(a!=null){
break;
}
if(b=="Ahhhhhhhhhhhhhhhhhhhh
running text
}
if(c=="good"){
running text
}
} while(false);
Hello, nice to meet you.
I think the example you gave me is an easy-to-understand code.
In my opinion, it is better not to fix it for readability.
However, use equals for string comparison in Java without exception.
if(a!=null){
if(b.equals("Ah"){
running text
}
if(c.equals("good")}
running text
}
}
Connect & (a!=null&&b.equals("Ahhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
Also, if the variable a is an argument for a function, you can use the @NotNull annotation to check the compilation check.It's definitely this direction these days.
public void yourCoolFunction(@NotNullfinalStringa){
if(b.equals("Ah"){
// Implementation
}
if(c.equals("good")}
// Implementation
}
}
Example code to reduce nesting.
if(a==null&b=="Ahhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
running text
}
if(a==null&c=="good"){
running text
}
It's not the point of the question, but I think it's better to use the equals method to compare whether the contents of the string are the same.
b.equals("Ah")
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