print('*'*20)
menu = int(input("""1. Add name
2. Delete Name
3. Modify Name
4. Termination
Select menu: "")
mylist = []
new_name = input('name :')
mylist.append(new_name)
print(mylist)
i=1
if menu == 1:
if i == 1:
print(mylist.append(new_name))
i+=1
else:
if new_name in mylist:
print(mylist)
else:
print ('Not Affected')
elif menu == 2:
if new_name in mylist:
print(mylist)
else:
print ('Not Affected')
elif menu == 3:
if new_name in mylist:
a = input ('new name:')
print(mylist.reverse(a))
else:
print ('Not Affected')
else:
break
In this process, an error called break outside loop appears. What should I do?
python
break
is used when you want to stop repeating in repetitive statements such as for
and while
and run the next code.
There is no repeat statement in the code you wrote, but an error occurs because you use break
.
Put the whole code inside the while
statement and try to correct it again
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