extract overlapping arrays from a two-dimensional array using python

Answer

>>>from collections import Counter
>>li = [[1, 2, 3], [5, 6, 7], [2, 3, 4, 5], [1, 2, 3], [7, 8, 9], [2, 3, 4, 5], [1, 2, 3], [5, 6, 7]]
>>>o=2
>>>c=Counter(tuple(x) for x inli)
>> [list(k)fork, vinc.items() if v==o]
[[2, 3, 4, 5], [5, 6, 7]]

It's not convenient for me to count on the list, so I chose a tuple once.
For non-overlapping data, we use set().

li = [[1, 2, 3], [5, 6, 7], [2, 3, 4, 5], [1, 2, 3], [7, 8, 9], [2, 3, 4, 5], [1, 2, 3, 3], [5, 6, 7]
tp=map(tuple,li)
tp

[(1,2,3),
(5, 6, 7),
(2,3,4,5),
(1, 2, 3),
(7, 8, 9),
(2,3,4,5),
(1, 2, 3),
(5, 6, 7)

pattern=tuple(set(tp))
pattern

((2,3,4,5), (5,6,7), (7,8,9), (1,2,3)

qty=map(lambdax:tp.count(x), pattern)
qty

[2,2,1,3]

data=zip(qty, pattern)
data

[(2,(2,3,4,5)),(2,(5,6,7)),(1,(7,8,9)),(3,(1,2,3)]

o=lambdanum:map(lambday:list(y[1]),filter(lambdax:x[0]==num,data))
o(3)

[[1,2,3]

o(2)

[[2,3,4,5], [5,6,7]