In Ruby, a program that performs division without using the division operator '/'

If you're telling me not to use /, all I have to do is use the alias div.

x=100
y = 3
z = x.div(y)
putz

Implement / because it's too sloppy on top.

def my_div(m,n)
  m.step(n, -n).count
end
x = 100
y = 3
z = my_div(x,y)
putz

There is a problem with this implementation.It means that it does not take into account the case where the divisor is 0 and/or the divisor is negative.If the divisor is 0, the ZeroDivisionError exception will be generated just like /.Also, in negative cases, the method of eliminating negative integers when there is a remainder is not uniquely determined unless it is divisible.Because the quotient depends on whether the remainder is always positive or the same sign as the divisor or divisor, how it is implemented depends on the programming language.This is the same sign as Ruby's behavior, or divisor.

def my_div(m,n)
  raise ZeroDivisionError if n.zero?
  return my_div (-m, -n) if n.negative?
  return-my_div (-m+n-1,n) if m.negative?
  m.step(n, -n).count
end
x = 100
y = 3
z = my_div(x,y)
putz

Negative calculations are a bit suspicious, so I'm sorry if there's a mistake.There is more than one way to implement it. You can also use +, -, *, and so on.

Now, the above method is not fast.The calculation amount is O(m/n), so if m is large, it will take a lot of time.If you apply the division method that you learn in elementary school, you should be able to process it faster, and there seems to be a method that uses bit calculation.I'm sure someone will respond to the fast implementation.