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Closed 5 years ago.
5 years agoCompilation error occurs below.
#include<stdio.h>
# include <stdlib.h>
# include <string.h>
int main() {
char*buf="<title>sample</title>";
char work [256];
char*p;
char*out=work;
char*in=buf;
in = strstr(in, "<");
while(strcmp((*p=(*out++=*in++))), "sample")!=0);
printf("%c",p);
// while(strcmp((*out++=*in++), ">")!=0);
*out='\0';
printf("%s\n", out);
return 0;
}
The following error appears:
01.c:In function 'main':
01.c:14:2:warning:passing argument 1 of 'strcmp' makes pointer from integer without a cast [enabled by default]
while(strcmp((*p=(*out++=*in++))), "sample")!=0);
^
Infile included from 01.c:3:0:
c:\mingw\include\string.h:43:37:note:expected 'const char*' but argument is of type 'char'
_CRTIMP int__cdecl_MINGW_NOTHROW strcmp(const char*, const char*)_MINGW_ATTRIB_PURE;
^
I'm sorry.Please point out the mistake.
If possible, please reply with the code.
That's faster to understand.Thank you for your cooperation.
Calm down and read the warnings and errors.
The strcmp function takes the char pointer type as the first argument, while *p is the char variable.
Also, the next line is
printf("%c",p);
%c is used to display char variables, but p is not correct because it is a char pointer type. Use %p if you want to display pointer values and %s if you want to display NULL termination strings.
char type and char pointer type seem to be confused. Check the difference between the two.
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