#include <stdio.h>
char stack[14] = "((9/2)*(4-2))";
int top = -1;
void h_push(int in)
{
top++;
stack[top] = in;
}
int h_pop()
{
int out;
out = stack[top];
top--;
return out;
}
int main() {
char input = 0;
char outpop;
int i;
for (int i = 0; i<14; i++) {
switch (stack[i])
{
case '(':
break;
case ')':
outpop = h_pop();
printf("%c", input);
break;
case '*':
input = '*';
h_push(input);
break;
case '-':
input = '-';
h_push(input);
break;
case '/':
input = '/';
h_push(input);
break;
default:
printf("%c", stack[top]);
}
}
}
There are countless empty spaces in the entertainment industry ``;
I don't think you're using the space with the input value (9/2)*(4-2) as a stack.
It's not... You made a stack space...
Just like the direction of the existing code, when it is ), spit out the stack and when it is +-/*, you can just increase the size of the stack by stacking it on the stack h
I think it would have been solved if I thought about it a little more, but I think it could be difficult if I am not familiar with coding/computer base.
#include <stdio.h>
char stack[14];
char text[14] = "((9/2)*(4-2))";
int top = -1;
void h_push(char in)
{
top++;
stack[top] = in;
}
int h_pop()
{
int out;
out = stack[top];
top--;
return out;
}
int main() {
int stacksize = 0;
char out;
for (int i = 0; i<14; i++) {
switch (text[i])
{
case '(':
break;
case ')':
for (int j=stacksize; j>0; j--) {
out = h_pop();
printf("%c", out);
}
stacksize = 0;
break;
case '*':
h_push(text[i]);
stacksize += 1;
break;
case '-':
h_push(text[i]);
stacksize += 1;
break;
case '/':
h_push(text[i]);
stacksize += 1;
break;
default:
printf("%c", text[i]);
}
}
}
© 2024 OneMinuteCode. All rights reserved.