This is a question about making 369 games related to Python.

/* 
    <Game Over Conditions >
       (1) If you enter a number incorrectly
       (2) If you enter a number when you need to enter a pair
       (3) You must enter a number, but if you enter a pair,
       (4) The number of inputs in the 'pair' does not match the correct answer

    < Input Exception Conditions >
        - If you enter all characters or strings except for non-numeric 'pair' (omitted) 
*/
---
/*
 * author: anonymous
 * * date: 06/01/2021 (m/d/y)
 * * purpose: QA answer
 */

#include <iostream>
#include <vector>

using namespace std;

void comInput(intn); // A function that outputs a computer input value (a value that is added to the user's input value is passed as a factor)

void printResult (const string & reason, answer); // a function that outputs results (outputs the number of times matched with the reason for ending the game)

int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);

    int user, answer;
    string s_user, s_answer, s_tmp;

    user = answer = 1;
    while (true)
    {
        cout << "-------------------" << '\n';

        s_answer = "";
        s_tmp = to_string(answer); //Split the correct value by digit through type conversion and store it in a string variable
        For (char c : s_tmp) // Store each digit of the correct answer stored in the string temporary variable repeatedly in the single character variable c
        {
            int x = c - '0'; // Convert a single character c to a single-digit integer and store it in the integer variable x
            If (x!=0 &&x%3 == 0) //x is a multiple of 3, store 'pair' in s_answer (cumulative by repeating the for-each statement)
            {
                s_answer += "even";
            }
        }

        If (s_answer.empty()) //s_answer is empty means that there is no multiple of 3 for each digit (=the answer is integer)
        {
            cout << "User input: ";
            cin >> user;
            If (cin.fail()) // if input fails (if text or string is entered) End game
            {
                printResult ("invalid input"), answer);
                break;
            }

            If (user == answer) //if correct, call computer input function
            {
                comInput(answer + 1);
            }
            else //if incorrect, exit game after incorrect answer output
            {
                printResult ("wrong"), answer);
                break;
            }
        }
        If there is one or more multiple of 3 in each digit of else //s_answer (= correct is a character or string)
        {
            cout << "User input: ";
            cin >> s_user;
            If (cin.fail()) //Failed (if you entered a number) End the game
            {
                printResult ("invalid input"), answer);
                break;
            }
            If (s_user == s_answer) //if correct, call computer input function
            {
                comInput(answer + 1);
            }
            else //if incorrect, exit game after incorrect answer output
            {
                printResult ("wrong"), answer);
                break;
            }
        }
        answer += 2; //The next character (integer or string) that the user enters will skip the computer input, so add 2
    }
    return 0;
}

void comInput(intn) { //A function that outputs a value that the computer will enter (the next number of correct answers entered by the user is taken as a factor)
    cout << "Computer input: ";
    strings_tmp = to_string(n); // Split the received factor value by digit through type conversion and store it in a string variable
    strings_answer; // declare string variable to accumulate 'pair'
    For (char c : s_tmp) //split the stored numbers one by one in a single character c
    {
        int x = c - '0'; // Convert a single character c to a single-digit integer and store it in the integer variable x
        If (x!=0 &&x%3 == 0) //x is a multiple of 3, store 'pair' in s_answer (cumulative by repeating the for-each statement)
        {
            s_answer += "even";
        }
    }
    If (s_answer.empty()) //s_answer is empty, it means that 3 or 6 or 9 is not included in the received factor, so output the factor as a number
    {
        cout << n;
    }
    else //if not, output s_answer with accumulated 'pair'
    {
        cout << s_answer;
    }
    cout << '\n';
}

void printResult(const string &reason, int answer) {
    cout << '\n';
    cout << "Game over:" << reason << '\n';
    cout << "Number of times correct: " <<< answer / 2 << '\n';
    cout << "-------------------" << '\n';
}