JAVA Scanner

int menu = scanner.nextInt(); System.out.print("The menu you want" + menu + "Is the number correct? (Y/N):"); String yn = scanner.next();

And then If you enter Y, the menu + "Number" order has been completed." If you enter N, please select the menu again." I'd like to print out.

I tried to write if(yn == y) but I got an error. Can't string be used as a conditional expression like int?

java

2022-09-22 22:56

1 Answers

Use in the form of yn == y to compare where the string is stored. If you want to compare the contents of a string, you must use it in the form of yn.equals(y).

2022-09-22 22:56

If you have any answers or tips

Popular Tags

python x 4647

android x 1593

java x 1494

javascript x 1427

c x 927

c++ x 878

ruby-on-rails x 696

php x 692

python3 x 685

html x 656