I'm asking you a question because I saw such a strange code.
I don't know why ([](){})()); is compiled normally in the source code below
I'm not a function pointer, I'm not an operator.
But if you run it on Visual Studio 2010, nothing comes out...
What is that doing?
int main(){
(([](){})()); // ??????
}
That code is called empty lambda.
I don't really do anything.
First, [](){} is empty lambda expression.
For convenience, let 1 = [](){} and (([](){})(); = ((A)();.
Second, parentheses expression in C/C++ have no effect on the code.
It does the same thing, whether it's in parentheses or not.
So you know up to here (A) = A.
Let's say B = (A) and ((A)(); = (B());.
Third, () is (empty) lambda.
Then let's say C = B() and (B(); = (C);.
(C) is parentheses the entire expression as we did in the second.
Then D = (C) and (C); = D;.
Lastly. ; is the role to end a sentence.
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