It's a code that my friend sent me, saying she found a weird function
1[a] It compiles well and executes well.
What's going on here?
int main(){
int* a = (int*)malloc(sizeof(int)*2);
a[0] = 1;
a[1] = 2;
printf("%d\n", a[1]);
printf("%d\n", 1[a]);//????????
}
The [] operator definition of the C standard is
a[b] == *(a + b)
This is.
That is, in this case
It is calculated as .
Addition is (a+1) = (1+a) because the exchange law is established,
Therefore, since the calculation results for these two are the same, finding the address value will result in the same result.
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