mylist1 = [1,2,3]
mylist2 = mylist1
mylist2 = []
This clears the existing reference. What I want is that if you change mylist2, mylist1 will also be emptied, so I can't use that code.
I'm writing it like this now, but I don't think my code is Python-like (?), so I'd like to get help from others.
while len(alist) > 0 : alist.pop()
mylist1 = [1,2,3]
mylist2 = mylist1
mylist2 = []
This code does not replace the existing list, but allocates an empty list ([]) so the existing reference is erased.
If you want to modify the list, not assign it, please look down
From 3.3, clear() can be used in the list.
mylist1 = [1,2,3]
mylist2 = mylist1
Mylist2.clear() #mylist1 also changed
Change the existing list using slices
mylist1 = [1,2,3]
mylist2 = mylist1
del mylist2[:]
It functions like 2.
mylist1 = [1,2,3]
mylist2 = mylist1
mylist2[:] = []
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