Please print out the error code and do not print the traceback

If you use pass in exception, you can't see what the error is at all, and if you don't take any action, there are a lot of tracebacks.

I want to know how to make it so that I can print only the error code and not print the traceback.

python exit traceback

2022-09-22 22:11

1 Answers

Then when an exception occurs

You can create a code that you do.

Write down your main routine like this

import sys, traceback

def main():
    try:
        #This is where the main code goes.
    except KeyboardInterrupt:
        print "Shutdown requested...exiting"
    except Exception:
        traceback.print_exc(file=sys.stdout)
    sys.exit(0)

if __name__ == "__main__":
    main()

2022-09-22 22:11

If you have any answers or tips

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