When using deque in C++, the type when using auto

How do I declare the same type of it in the for statement in the code below?

It doesn't come out properly even if I use typeid

My prediction is std::deque::iterator, is that right?

#include <iostream>
#include <deque>
#include <typeinfo>

using namespace std;

int main(){
      deque<int> dep;

      dep.push_back(10);


      int nSum=0;

      for(auto it = dep.begin(); it != dep.end(); it++){
            nSum += (*it);

            cout << typeid(it).name() << endl;
      }

      cout << nSum <<endl;

      return 0;
}

c++ stl c++11

2022-09-22 21:10

1 Answers

You can define the type, such as std::deque<int>::iterator it.

Looking at the definition of begin in the decque, it comes out.

// deque::begin
#include <iostream>
#include <deque>

int main ()
{
  std::deque<int> mydeque;

  for (int i=1; i<=5; i++) mydeque.push_back(i);

  std::cout << "mydeque contains:";

  std::deque<int>::iterator it = mydeque.begin();

  while (it != mydeque.end())
    std::cout << ' ' << *it++;

  std::cout << '\n';

  return 0;
}

2022-09-22 21:10

If you have any answers or tips

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