var num = 11;
(num > 100) && num++;
document.writeln ("num: "+num+"<br/>"); //value num: 11
(num < 100) || num++;
document.writeln ("num: "+num+"<br/>");//value num: 11
(num < 100) && num++;
document.writeln ("num: "+num+"<br/>");//value num: 12
(num > 100) || num++;
document.writeln ("num: "+num+"<br/>");//value num: 13
document.writeln("12&1 : "+!(12&1)+"<br/>");//12&1 : true
document.writeln("13&1 : "+!(13&1)+"<br/>");//13&1 : false
The value comes out like this, but I don't know if the value of the variable increases one by one from the third. Can you explain why the last part is "true" and "false"?<
javascript && ||
Everything is as you wish...
Left && Right Side
The AND operator omits the evaluation ()execution) of the right side when the left side is false and the result is false even if the right side is false.
Left || Right Side
The OR operator omits the evaluation of the right side when the left side is true and the other side is true.
If you look at each line based on the top:
var num = 11;
(num > 100) && num++; // Left side is false, so right side is omitted
(num < 100) || num++; // Left side is true, so right side is omitted
(num < 100) && num++; // Run to right side because left side is true. num is 12
(num > 100) || num++; // Run to right side because left side is false, num is 13
It's going to be it.
The calculation result of 12 & 1 is 0. && is called logical AND, and & is called bit AND, which is different.
console.log(12..toString(2)) /* "1100" */
console.log(1..toString(2)) /* "1" */
The bit AND result of console.log (12 & 1) /* 1100 and 0001 is 0000 */
End.
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