name = input ('Enter file name: ')
if len(name) > 1 :
name = 'mbox-short.txt'
filename = open(name)
for line in filename :
if 'From ' in line :
print(line.rstrip)
else :
continue
print(filename)
(1)
I'm practicing the code to filter emails in the document through Cocera. I was lazy to type the file name, so I used the len code that Professor Kosera also used, but for some reason, there is a message that I couldn't find the file or directory due to traceback in the fourth line variable. Why is this problem even though I didn't enter the wrong file name? What am I doing wrong?
(2)
If you don't use .rstrip, you can find and print out words without any problems, but if you put .rstrip, The value has been changed to built-in method rstrip of strip object at 0x03DSEA88 and is being output. Whether you get the price you want. Whether you get it or not, the message <_io.TextIOWrappername='mbox-short.txt'mode='r'encoding='cp1252'> is printed at the end, how do I get rid of these messages and get the value I want to get? What's wrong with this problem?
Please give me some advice.
python len rstrip
(1)
I think it'd be nice if you put up the backtrace as well.
Traceback occurs, prompting you to say that the file, directory, could not be found.When you say , it seems that an exception occurred in filename = open(name).
If the purpose is to create a file with name, you need to set the mode as below.
filename = open(name, "w")
(2)
rstrip is a function.
Therefore, it is called only when it is opened and closed in parentheses, such as rstrip().
So try modifying it like print(line.rstrip().
In addition, print(filename), <_io.TextIOWrapper name='mbox-short.txt' mode='r' encoding='cp1252'> is displayed because the filename=openname became a file.
Of course, you can erase this output code if you want to raise it.
© 2024 OneMinuteCode. All rights reserved.