[Python Python basics] What's the problem?


n=int(input("user input :"))


numlist= [2];
listnum=1;
def numberOfPrime (n):
    for i in range(3,n):    
        if (n % i == 0):            
            numlist.append(n)
            listnum+=1;
            return numlist
            return listnum
        else:
            return print ("Output X because it is not a decimal")

print(numberOfPrime(n))

If it's a decimal, add it to the numlist Or I'm trying to make a def that says no What's the problem?

python

2022-09-22 19:11

1 Answers

n=int(input("user input :"))


numlist= [2];
listnum=1;
def numberOfPrime (n):
    global  numlist
    global  listnum
    for i in range(3,n):    
        if (n % i == 0):            
            numlist.append(n)
            listnum+=1;
            return numlist ,listnum
        else:
            return "Output X because it is not a decimal"

print(numberOfPrime(n))

Grammarly, I think we need to revise this much. This does not mean that the algorithm is correct.

If you do not use the keyword global, the listnum in the function is considered a regional variable. However, an error occurs because it is used for calculation without initializing.

Interestingly, even if you omit the global numlist, the numlist is understood as a global variable.

In numlist.append(n), numlist is understood as an instance that already exists, so it is found in the global variable because it is not found in the local area.

numlist =  numlist + [n] ( numlist  += [n] )

This results in the same error as listnum+=1.

2022-09-22 19:11

If you have any answers or tips

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