Hi, how are you?
For example, the file name has the following specific patterns:
3G1-1EW_E-W_ACC
3G1-1NS_N-S_ACC
3G1-1UD_U-D_ACC
3G1-2EW_E-W_ACC
3G1-2NS_N-S_ACC
3G1-2UD_U-D_ACC
When referred to as abc-def_g-h_ijk
Can a, b, c, and d find the same file name and extract it??
For example, there are 6 files in the list as shown above
3G1-1EW_E-W_ACC
3G1-1NS_N-S_ACC
3G1-1UD_U-D_ACC
Find and extract only 3 files that meet the conditions as follows If you have a file
file1=pd.read_csv('3G1-1EW_E-W_ACC')
file2=pd.read_csv('3G1-1NS_N-S_ACC')
file3=pd.read_csv('3G1-1UD_U-D_ACC')
Specify as pd.concat and merge the 3G1-1.csv files with pd.concat
Go back to
file1=pd.read_csv('3G1-2EW_E-W_ACC')
file2=pd.read_csv('3G1-2NS_N-S_ACC')
file3=pd.read_csv('3G1-2UD_U-D_ACC')
Similarly, you would like to merge the 3G1-2.csv files.
ii = [i for i in os.listdir(targerdir) if '3G1-1' in i]
I did the fairy degree, but I had to change the conditional sentence 3G1-1 every time,
Do you have any other routines?
Please keep that in mind.
L = [
'3G1-1EW_E-W_ACC',
'3G1-1NS_N-S_ACC',
'3G1-1UD_U-D_ACC',
'3G1-2EW_E-W_ACC',
'3G1-2NS_N-S_ACC',
'3G1-2UD_U-D_ACC'
]
import itertools as it
g = it.groupby(L, lambda name:name[:5])
for k, v in g:
print(k, list(v))
3G1-1 ['3G1-1EW_E-W_ACC', '3G1-1NS_N-S_ACC', '3G1-1UD_U-D_ACC']
3G1-2 ['3G1-2EW_E-W_ACC', '3G1-2NS_N-S_ACC', '3G1-2UD_U-D_ACC']
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