Hello, everyone I am a student studying c++.
I am inquiring because there is something strange while studying c++.
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char c = 'a';
char *d = &c;
cout << d << endl;
printf("%p\n",d);
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I understand that the address value of mode c will be printed in two cases if it is done as above.
However, in the case of cout, it is not an address value, but a strange value is continuously printed, so I want to know why.
c++ c printf cout char*
Printf sets the format to %p, i.e. explicitly output the address.
cout is outputting variable results, not addresses.
The reason why the strange value is output is that char* is a little unique, unlike other types. char* is also the definition of a string, with the end of the string definition being null characters. That is, it recognizes that before the null character is a single string, so it is output together until a strange value, that is, null appears.
Just memorize this part. Char* is different from int*. Char* must represent a string, and the string ends with a null character. The variable name also represents a string value, not an address.
In other words, if you do cout <<d, you print it out until you get a null character, even though you substituted only one character. If you want to output only one character, you must express it explicitly, such as d[0].
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