I want to bring it to soup and run it only if there is a specific class

Asked 2 years ago, Updated 2 years ago, 79 views

When Africa BJ starts broadcasting, I'm going to make a program that executes a specific code.

If you look at the BJ station website, there is a live class only when broadcasting.

So I crawl the BJ broadcasting station's homepage every certain period and if there is a live class, a specific code

I want to do it, but I'm stuck in comparison, so I'm looking for help Below are some of the sources

url2 = 'http://bj.afreecatv.com/devil0108'
driver = webdriver.Chrome()
driver.implicitly_wait(3)
driver.get(url2)

html = driver.page_source
soup = BeautifulSoup(html, 'html.parser')

r = soup.select('.live')

if r == '<span class="live">LIVE</span>':
    driver.close()
    print ("Live")

else:
    driver.close()
    print ("Not Live")

I opened the home with selenium in JavaScript and saved the live class in r and printed it out.

<span class="live">LIVE</span> was displayed like this

So if r is <span class="live">LIVE</span>, I want to execute the code below.

I don't know if the comparison was wrong, but it just came out that it wasn't on live.

I'm looking for help because I can't try the if part with "

python beautifulsoup crawling

2022-09-22 17:59

1 Answers

Try it as below.

The r can be none, so I'll have to take the code for that code.

ifr.text == 'LIVE': driver.close() print ("Live")
else: driver.close() print ("not live")


2022-09-22 17:59

If you have any answers or tips


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