Sorting result not output...

Asked 2 years ago, Updated 2 years ago, 68 views

I was simply creating a sort selector.

The five integers entered by the user are sorted by heap, bubble, and quick.

t = 0
print("Please enter 5 integers of your choice:\n")
unsorted = []
sorted = []

while t < 5:
          n = input()
          unsorted.append(n)

print("Is there any sort method you want?\n")
print("1. Hip sort 2. Bubble sort 3. Quick sort\n")
call = input()

def heapsort(unsorted):
        size = len(unsorted) #alignmentsize
        for i in range(size, -1, -1) : heapify(unsorted, size, i)
        for i in range(size-1, -1, -1) :
                unsorted[i], unsorted[0] = unsorted[0], unsorted[i]
                heapify(unsorted, i, 0)

def heapify(a, size, i):
        largest = i
        L = 2 * i + 1
        R = 2 * i + 2
        if L < size and a[L] > a[i]:
                largest = L
        if R < size and a[R] > a[largest]:
                largest = R
        if largest != i:
                a[largest], a[i] = a[i], a[largest]
                heapify(a, size, largest)

if call == 1:
        heapsort(unsorted)
        print("Sort result is like this.\n")
        print(unsorted)

When I build it, I can't print out what the sorting result is like

How can I make it work properly?<

python sorting

2022-09-22 16:57

1 Answers

call = int(input()) If you enter 1, the call becomes an integer of 1. If you just say call = input(), it will be the string you entered, that is, "1". "1"!=1.


2022-09-22 16:57

If you have any answers or tips


© 2024 OneMinuteCode. All rights reserved.