for example
There's a list called a = []
If there may be an empty value when adding a value using a repeat or conditional statement, as shown in the following equation
I wonder if I can make a list compilation.
if not a:
pass
else:
a.append(value)
This is...
print(sum[if not a pass else a.append(value)])
If there's no price like this, I want to make you do something if it's going over, but even if you google it, There are all For statements in it, so I wonder if I have to use the For statements and the If statements together.
python
Although it is not list compliance, filter would be useful in this case.
You can write it like this. Let's say you only take 1 out of the list a
a = [1, 2, 3, 2, 5, 1, 7, 1]
b = list(filter(lambda x: x == 1, a))
print(b)
You can use a code like this.
Yes, you can.
List Compensation is briefly,
[Value.Method for value in set if condition]
Because it's a concept, the example sentence you mentioned
if not A:
pass
else:
a.append(value)
If you translate (?) directly into the list,
[value for value in a if not A] #It's a little awkward...
This is.
Let me show you some simple examples.
# Example 1) I want to output the sum of integers that are multiple of 3 or 5 in the list
a = [1,2,3,4,5,6,7,8,9,10]
print(sum([i for i in a if i % 3 == 0 or i % 5 == 0]))
# Result: 33
# e.g. 2) Select only strings with a length of 4 or greater from the string list and use uppercase letters, and lowercase letters for the rest
List = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten"]
print([value.upper() iflen(value) > 3 else value.lower() for value in list ])
# Results: ["one", "two", "THREE", "FOUR", "FIVE", "six", "SEVEN", "EIGHT", "NINE", "ten"]
#Example 3) It doesn't have to be a method.
print (["even" if value %2 == 0 else "odd" for value in a])
#Result: [Odd number, even number, even number, even number, even number, even number, even number, even number, even number, odd number, even number, even number, even number, even number]
Please ask more specific questionsh
It's been a long time;
If you add...
numbers = [1, 2, 3, 4, 5, 5, 5 , 7, 8, 9, 10]
summation = sum([number for number in numbers if number == 5])
print (summation)
If you want to select a specific number and save it to a new list,
get_num = [number for number in numbers if number ==5]
print(get_num)
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