import java.util.Scanner; import java.util.Arrays;
public class test1 { public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int[] num;
num = new int[7];
int[] num2 = new int[7];
System.out.print("Please enter 6 numbers and 1 bonus number! :");
for (int i = 0; i < num.length; i++) {
num[i] = scan.nextInt();
for (int j = 0; j < i; j++) {
if (num[i] == num[j]) {
i--;
System.out.print ("Number is duplicated". Please re-enter! : ");
break;
}
}
}
System.out.println(Arrays.toString(num));
scan.close();
}
}
If you run the code above, you put a break, but you said, "The numbers are duplicated. Please re-enter! : The sentence " is printed 6 times and ends. I don't know what I'm missing. Please give us feedback.
java
for (int j = 0; j < i; j++) {
if (num[i] == num[j]) {
The meaning of the above code is to compare all numbers in num[i] and num to see if they are the same.
If you put a value in num[i] in the upper line, num must have num[i] so that if must match once.
So the number 6 is duplicated. Please re-enter! : will be printed.
To solve this problem, we can change if to exclude num[i] from the comparison, right?
if (i != j && num[i] == num[j]) {
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