import random
cum=random.sample(range(1,10),4)
print(cum)
def check_list(listname,input_num):
listname=[]
while len(listname)<=input_num-1:
z=0
num=int ("Enter a number")
listname.append(num)
for k in range(len(listname)-1):
for j in range(k+1,len(listname)):
if listname[k]==listname[j]:
print("Duplicate value exists". Please re-enter it.")
listname=[]
strike=0
ball=0
for n in range(len(cum)):
for r in range (len(listname)):
if cum[n]==listname[r]and n==r:
strike=strike+1
elif cum[n]==listname[r]:
ball=ball+1
print(strike,"-strike",ball,"-ball")
if strike==4:
print(z"revised successfully!")
else:
z=z+1
check_list(listname,input_num)
play=[]
check_list(play,4)
I made a code for a baseball game, but how do I write the number of times? Since I reset it to a recursive function, the count of the number of times is reset to zero, so the number of times cannot be saved. Is there a solution or do I have to rewrite the code?
function
No recursion required.
import random
cum = random.sample(range(1, 10), 4)
print(cum)
def check_list(input_num = 4):
cnt = 1
while True:
num = input ("Enter a number")
#if not num.isnumeric() or len(num) != input_num or len(set(num)) != input_num:
if (num.isnumeric(), len(num), len(set(num))) != (True, input_num, input_num):
print('Number only, number {} must be entered, duplicate values are not allowed'.format(input_num)))
continue
solve = [v1 == v2 for v1, v2 in zip(cum, map(int, num))] # True, False to distinguish strikes and balls.
strike, ball = solve.count(True), solve.count(False)
print("{}-strike {}-ball".format(strike, ball))
if strike == input_num:
print("{}Successful conversion!"format(cnt))
return
else: cnt += 1
check_list()
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