From the source code below,
What does x^0x1 do?
What rules do I not know?
if( 0 != ( x ^ 0x1 ) )
encode( x, m );
0x1 means hex 1.
If you look at the truth table of the XOR operation,

You can see that xor 1 returns true if x is 0, and false if x is 1.
In other words, (x^0x1) checks whether x is 0 or not
In other words, (x^0x1) = (x!=1).
You have to see the whole code It seems like a difficult code on purpose.
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