To have a function output its own name without a traceback module

How do you get a function to output its own name without a traceback module?

For example, when the module foo has a bar function, in foo.bar() you would like to print bar is your name "bar" or "foo.bar".

What should I do now?

#foo.py  
def bar():
    print "my name is", __myname__ # How do I print this out?

2022-09-22 11:50

1 Answers

There is no function in Python that determines its own name. It's been suggested before, but it's been rejected.

So if you want to print out your name,

def bar():
    print "my name is bar"

    #or
    print "my name is foo.bar"

def bar():
    print "my name is", bar.__name__

import inspect

def foo():
   print inspect.stack()[0][3]

2022-09-22 11:50

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