How do I subtract a day from a datetime object?

datetime.datetimeIf you are operating on an object, you usually write datetime.timedelta()

The circular form of the datetime.timedelta() function is datetime.timedelta([days[,seconds[,microsconds[,milliseconds[,minutes[,hours[,weeks]]]]]]]]) The default value for all factors is 0, and you can receive int, long, and float regardless of positive or negative.

Here's how to write:

from datetime import datetime, timedelta

d = datetime.today() - timedelta(days=1)