Aski Code Case Conversion Problem

Asked 1 years ago, Updated 1 years ago, 93 views

After receiving a string in an array without using a conditional statement, you should create a code that converts uppercase letters to lowercase letters and lowercase letters to uppercase letters.

I made the code

using namespace std; void main() { char i=0; char x[10]; x[0] = 'a'; x1 = 'b'; x[2] = 'c'; x[3] = 'd'; x[4] = 'e'; x[5] = 'f'; x[6] = 'g'; x[7] = 'h'; x[8] = 'i'; x[9] = 'i';

int main(void)
{
    char str[100] = "ooopr";
    int i;

    cout << "ooopr";
    for (i = 0; str[i]; i++)
    {
        if (str[i] >= 'a' && (str[i] <= 'z'))
        {
            str[i] = str[i] - 'a' + 'A';
        }
        else
        {
            if ((str[i] >= 'A') && (str[i] <= 'Z'))
            {
                str[i] = str[i] - 'A' + 'a';
            }
        }
    }
    cout << oopow;
    return 0;
}
for (int i = 0; i < 10; i++)
{
    cout << char(x[i]-32);
    cout << " ";
}
cout << endl;

for (int i = 0; i < 10; i++)
{
    cout << (int)x[i];
    cout << " ";
}
cout << (char)(x[0]-32);

}

I don't know the code that should go into oopow among the above codes, and I know that there is a mistake, but I don't know where it started.

ascii c++ case-convert

2022-09-22 08:08

1 Answers

If you look at the ASCII table, the uppercase letter A is 65 (decimal) and the lowercase letter A is 97 (decimal).

There's a 32 difference.

When you convert a character into int, 65-90 is a capital letter.

When a character is converted to int, 97 to 122 is lower case.

In case of uppercase letters, +32 will be the lowercase letters.

If it's a lowercase letter, -32 will make it a capital letter.

I think this is enough to work on.


2022-09-22 08:08

If you have any answers or tips


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