Javaio and Carriage Return

Hello. Thank you for always giving me a good answer! I study alone, but whenever I find it difficult to understand even if I search on Google, I am looking for a hash code. Thank you very much.

I'm studying io, but the output value is weird, so I'm here to ask.

package streamEx;

import java.io.IOException;

public class inputStreamTest2 {

    public static void main(String[] args) {
        byte[] input = new byte[5];

        int i = 0;
        int cnt = 0; // count
        int tot = 0; // total
        System.out.println ("Enter in the control window!");
        try {
            while((i= System.in.read(input)) != -1){ 
                cnt++; // Number of repeat statements
                tot += i;

                System.out.println("i: "+i);
                System.out.write(input, 0, i);

            }    }    System.out.println("cnt: "+cnt);

            System.out.println ("byte count read: "+tot");
            System.in.close();
            System.out.close();
        } } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

If I type AppleTest in Eclipse,

i: 5
Applei: 5
Test
i: 1

Is it printed like this?

i: 5
Applei: 5
i: 1t

This is how it's printed.

In my opinion,

i: 5
Applei: 5
i: 1
Test

I thought it should be

And why is there a difference between the output of Eclipse and cmd?

I have a question about the memory structure for the array. If you look at the source, I declared a 5-byte array called input, but when I put the word "AppleTest", I typed 11byte including '/r'/n', but I wonder why it doesn't overflow and why it's all output. If you look at the description, you can see the input stream

"_____/n/rt test TELEPA"(_ is blank.)

It's input Output stream has

" i:5\nApllei:5Test\ri:1\n\n "

It says input is done as input[0] = "Apple", input[1] = "Test\r", input[2] ="\n" Are you saying it goes in like this?

Be careful not to catch a cold since it doesn't catch a cold~~~