How to enter an integer in C++ at once without any spaces

When you get a fixed income In C, scanf ("%1d", & array) can be entered at once Is there a way to get it without any gaps without using scanf on C++? All I know is to receive it as a string and convert it, but I think it's too much trouble <

c++

2022-09-21 21:28

1 Answers

I think it would be nice to read one letter at a time and convert it into a number like the code below.

#include <iostream>

int main() {
    int inputs[10];

    for (int& digit : inputs)
        digit = std::cin.get() - '0';

    for (int digit : inputs)
        std::cout << digit;

    return 0;
}

Or you can create a function like this to make it easier to use.

#include <iostream>

template<typename T>
struct Digits
{
    typedef T* iterator;
    iterator begin, end;

    template<typename U, std::size_t size>
    Digits(U (&arr)[size]) : begin(arr), end(arr + size) {}
    Digits(T* arr, std::size_t size) : begin(arr), end(arr + size) {}
};

template<typename T>
std::istream& operator>>(std::istream& s, Digits<T> v)
{
    typedef typename Digits<T>::iterator iterator;
    for (iterator itor = v.begin, end = v.end; itor != end; ++itor)
        *itor = static_cast<T>(s.get() - '0');
    return s;
}

int main() {
    int inputs[10];

    std::cin >> Digits<int>(inputs);

    for (int digit : inputs)
        std::cout << digit;

    return 0;
}

2022-09-21 21:28

If you have any answers or tips

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