stack = [3, 4, 5, 8, 0]
print('stack : [')
for x in stack:
print(stack[x], end='')
if x >= 4:
print(']')
break;
As above, I tried to check if the value is output after declaring and assigning a list variable called stack. However, I don't understand why it's like this when you actually run it and only stack = [80].
I thought x would start with the zero subscript and then stack[0] = 3 and print it out, but the result is different from what I thought.
What do I misunderstand?
python list indexing
When for x in stack:, x contains the values in the stack one by one.
So, I have to print(x) instead of print(stack[x]). Did you happen to want this to happen?
stack = [3, 4, 5, 8, 0]
print('stack : [')
for x in stack:
print(x)
print(']')
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