import random
import collections
from collections import Counter
a=Counter()
number_list=list(range(1, 100)
for i in range(10) :
c= random.sample(number_list, 10)
a.update(c)
c.sort()
print(c)
common=[m[0] for m in a.most_common(6)]
common.sort()
print(common)
=> Out of the 10 repetitions, it's not just the 10 most number I'd like to pick the 10 most out of the 3 or more numbers. And if there are no more than three, I want to make a program that runs from scratch again, but I don't know the corresponding function or command. I just joined Python, so I don't know much. Please give me a kind reply.
python
I don't know if it's a kind answer, but there's no function like a silver bullet that results at once.
import random
from itertools import groupby, repeat, chain
number_list=list(range(1, 100))
random_numbers_per_row = (random.sample(number_list, 10) for i in range(10))
flatten_numbers_with_sorted = sorted(chain(*random_numbers_per_row))
groupby_numbers = groupby(flatten_numbers_with_sorted)
groupby_numbers2 = ((list(v)) for k, v in groupby_numbers)
solve_numbers = list(filter(lambda item:len(item) > 2, groupby_numbers2))
print(sorted(solve_numbers, key=len, reverse = True))
[[31, 31, 31, 31, 31], [70, 70, 70, 70, 70], [3, 3, 3, 3], [32, 32, 32, 32], [28, 28, 28], [34, 34, 34], [58, 58, 58], [75, 75, 75]]
The above algorithms are as follows:
© 2024 OneMinuteCode. All rights reserved.