The school gave it to me as an assignment
I don't know what this code is doing or why it's running normally
>>>=What is this doing?
Why is the output ????
#include <stdio.h>
int main()
{
int a[2]={ 10, 1 };
while( a[ 0xFULL?'\0':-1:>>>=a<:!!0X.1P1 ] )
printf("?");
return 0;
}
while( a[ 0xFULL?'\0':-1:>>>=a<:!!0X.1P1 ] )
If you open one by one,
Replace the double characters :> and <: with and [, respectively
while( a[ 0xFULL?'\0':-1] >>=a [!!0X.1P1 ] )
and xfull, 0 is true because , '\ 0' : -? 0 xfull 1 is simple, can simply as 0 is '\ 0'
while( a[0] >>=a [!!0X.1P1 ] )
and 0. 1 The 1 p x express floating-point decimal and hexadecimal numbers, 0.125. This is always because it is not zero true as .
! 0. is 1 1 1 p x.
while( a[0] >>=a[1] )
> > = operator is going to see. Shift the left prices for a value on the right side of the. A [1] = 1, in reality,
while( a[0] >>= 1 )
if you write differently, and while (a [0] / = 2) and the same.
In the first while loop, a[0]/2 = 5-> "?"Output
In the second while loop, a[0]/2 = 2-> "?"Output
In the third while loop, a[0]/2 = 1-> "?"Output
In the fourth while loop, a[0]/2 = 0 -> while statement ends
Because of that's why?It will be printed three times.
© 2024 OneMinuteCode. All rights reserved.