a = [('2019-05-01',),('2019-05-02',)...(n)] #sqlitedatetupleb value to be modified
b = ((2019, 5, 1), (2019, 5, 2)...(n)) #Calendar date tuple fixed value not changed
for i in range(len(a)):
print(''.join(a[i]).replace('-', ','))
There are a,b values above, and you want to make the value a the same as the value b. The problem is that if you output a value above,
2019,05,01
2019,05,02
It comes out, but if I erase the value of 0 per month and day with 'replace', the value of 0 per year is erased, so I tried to erase it using the regular expression and make it into a tuple, so I couldn't tie it with inttuple So what I thought was to make it a = year, month, and day by giving three separate variables, but this doesn't work well, and I want to get help from other good methods.
python
a = [('2019-05-01',),('2019-05-02',),('2019-05-03',)]
b = []
for i in range(len(a)):
temp = a[i][0].split("-")
temp[1] = str(int(temp[1]))
temp[2] = str(int(temp[2]))
b = b + [(", ".join(temp),)]
print(b)
>>>
======= ======= RESTART: C:/Users/USER/Desktop/aaa.py =======
[('2019, 5, 1',), ('2019, 5, 2',), ('2019, 5, 3',)]
You can transform one by one like the top, but Python keeps the code simpler if you think of it as a collection, that is, as a lump and program it.
d1 = '2019-05-01'
y, m, d = map(int, d1.split('-')) # Date of year int Type transformation and place it in the variable
triple(map(int, d1.split('-')) # Int-type conversion result is generated as a triple immediately
Chain (*a) is a platten treatment by peeling off the tuple of a.
In [19]: a = [('2019-05-01',), ('2019-05-02',)]
In [20]: list(chain(*a))
Out[20]: ['2019-05-01', '2019-05-02']
Finally, you can fill it out as below.
In [43]: from itertools import chain
In [44]: a = [('2019-05-01',), ('2019-05-02',)]
In [45]: b = tuple(tuple(map(int, item.split('-'))) for item in chain(*a))
In [46]: b
Out[46]: ((2019, 5, 1), (2019, 5, 2))
In [47]: [tuple(map(int, item.split('-'))) for item in chain(*d)]
Out[47]: [(2019, 5, 1), (2019, 5, 2)]
© 2024 OneMinuteCode. All rights reserved.