Like the zip code, we're going to print an integer that matches 5 to 6 digits Is there an easier way than the code I made?
/*
num : Integer to output,
len : Number of digits
*/
void printWith0(int num, int len){
int num0 = len-num/10;
int i;
for (i=1; i<num0; i++) {
printf("0");
}
printf("%d", num);
}
int main() {
int mynum = 1;
printWith0(mynum, 5);
}
c has a format specifier that supports this feature.
Attach 0
immediately after the specifier %
followed by a digit, then add a format specifier that fits the type
However, in the case of floating points, it means to fill in 0 to n decimal places, not integer parts, so please write the two separately.
Example:
int main() {
printf("%05d\n", 303);
printf("%010d\n", 303);
printf("%05f\n", 3.03);
}
Output:
00303
0000000303
3.030000
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