def ndiv(l,n):
return [l[i:i + n] for i in xrange(0, len(l) // n * n, n)] + [[e] for e in l[len(l) // n * n:]]
print "INSERTION : {}".format(ndiv(insertion, i))
print "INSERTION1 : {}".format(ndiv(insertion1, i))
ds = [sum(sd) for sd in ndiv(insertion,i)]
sa = [sum(aa) for aa in ndiv(insertion1,i)]
ss = [x+y for x,y in zip(ds,sa)]
for ada in ss:
log2 = math.log(float(i + 1), 2)
qq = 3 * ada * (log2)
print "Each Insertion : {}".format(qq)
print "JOINING : {}".format(ndiv(joining, i))
print "JOINING1 : {}".format(ndiv(joining1, i))
aa = [sum(ad) for ad in ndiv(joining,i)]
bb = [sum(ac) for ac in ndiv(joining1,i)]
cc = [x+y for x,y in zip(aa,bb)]
for qwe in cc:
log2 = math.log(float(i + 1), 2)
ab = 4 * qwe * (log2)
print "Each Insertion : {}".format(ab)
Hello, I want to take out the result value calculated through the for statement separately and add it (the result value of each for statement), but I'm asking you because I don't know what to do.
ex) compute = qq + ab
The logic is the same, so separate it with a separate function
# Return all field values in ss, cc list
def sumOfList(v_list, multiply):
result = []
for item in v_list:
log2 = math.log(float(i + 1), 2)
qq = multiply * item * (log2)
print "Each Insertion : {}".format(qq)
result.append(qq)
return sum(result)
def ndiv(l,n):
return [l[i:i + n] for i in xrange(0, len(l) // n * n, n)] + [[e] for e in l[len(l) // n * n:]]
print "INSERTION : {}".format(ndiv(insertion, i))
print "INSERTION1 : {}".format(ndiv(insertion1, i))
ds = [sum(sd) for sd in ndiv(insertion,i)]
sa = [sum(aa) for aa in ndiv(insertion1,i)]
ss = [x+y for x,y in zip(ds,sa)]
# Sum is received using the function
sumOfSs = sumOfList(ss, 3)
print "JOINING : {}".format(ndiv(joining, i))
print "JOINING1 : {}".format(ndiv(joining1, i))
aa = [sum(ad) for ad in ndiv(joining,i)]
bb = [sum(ac) for ac in ndiv(joining1,i)]
cc = [x+y for x,y in zip(aa,bb)]
# Sum is received using the function
sumOfCc = sumOfList(cc, 4)
# adding two results
compute = sumOfSs + sumOfCc
Hm... aside from code errors
If you let me know the result you want
Assign the for statement in the same indent block declared.
for ada in ss:
# ...
# qq = 3 * ada * (log2) <= qq declaration and value assigned
# ...
for qwe in cc:
# ...
# ab = 4 * qwe * (log2) <=ab declaration and value assigned
# ...
compute = qq + ab
It's not this question If there's a logic problem or an error, Please let me know the phenomenon and organize the code again and upload it.
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