When you know the minimum and maximum values, you want to store all the integers in between in an array, including these.
#include <iostream>
#include <vector>
int main() {
std::vector<int> arr = { 0, };
int min = 2;
int max = 8;
int idx = 0;
for (int i = min; i <= max; i++) {
arr[idx++] = i;
}
std::cout << arr[0] << "\n";
return 0;
}
Compiling the above code
main: malloc.c:2401: sysmalloc: Assertion `(old_top == initial_top (av) && old_size == 0) || ((unsigned long) (old_size) >= MINSIZE && prev_inuse (old_top) && ((unsigned long) old_end & (pagesize - 1)) == 0)' failed. Aborted (core dumped)
This error does not output the value of arr[0]. It's hard to even interpret the error message, how can I solve it?
c++ vector
You created a vector with a size/capacity of 1 at the time of vector creation
I think it's because it's assigned by accessing the index outside the vector range (arr[idx++]) while going around the for door.
When you make an arr, you can know the size, so make it to secure space in advance.
std::vector<int> arr(max - min + 1);
Or how about using arr.push_back(value); instead of assigning the value with arr[idx] = value; for dynamic allocation?
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