This is the process of adding a constructor to an existing inheritance class code.
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No instance of constructor MyFriendDetailInfo::MyFriendDetailInfo matching argument list MyFriendDetailInfo:::MyFriendDetailInfo(char*, int, char*): Argument 1 is: Cannot convert from const char[7] to char*
Two of these errors appear.
I've removed the extinction
class MyFriendInfo
{
private:
char* name;
int age;
public:
MyFriendInfo()
{
}
MyFriendInfo(char* name, int age)
{
int len = strlen(name) + 1;
name = new char[len];
}
void ShowMyFriendInfo()
{
cout << "Name: " << name << endl;
cout << "Age:" <<age << endl;
}
};
class MyFriendDetailInfo : public MyFriendInfo
{
private:
char* addr;
char* phone;
public:
MyFriendDetailInfo(char* name, int age, char* addr, char* phone)
:MyFriendInfo(name, age)
{
int len = strlen(addr) + 1;
addr = new char[len];
len = strlen(phone) + 1;
phone = new char[len];
}
void ShowMyFriendDetailInfo()
{
ShowMyFriendInfo();
cout << "주소: " << addr << endl;
Cout < < "Call :" < < phone < < endl < <. ; endl
}
};
int main()
{
Myfrienddetailinfo friend. 1 ("name", 23, "address", "010") ;
Friend1.ShowMyFriendDetailInfo();
return 0;
}
Because a literal string such as "Name" is a non-modifiable string, the address cannot be stored in the char * type pointer, and the address must be stored in the const char * type pointer.
MyFriendDetailInfo(char* name, int age, char* addr, char* phone)
Therefore, code such as MyFriendDetailInfoFriend1("Name", 23, "Address", "010"); needs to be modified as below.
MyFriendDetailInfo(const char* name, int age, const char* addr, const char* phone)
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