If you do it like this, it's printed indefinitely. What's wrong with this? I don't understand the exact purpose of Iteratoriter = set1.iterator();
import java.util.*;
public class Generic1 {
public static void main(String[] args){
Set<String> set1 = new HashSet<>();
boolean yesorno = set1.add("dada");
set1.add("dsafd");
set1.add("dfdsa");
set1.add("dfds");
System.out.println(yesorno);
System.out.println(set1.size());
while(set1.iterator().hasNext()){
String str = set1.iterator().next();
System.out.println(str);
}
}
}
Tryhelloworld's http://tryhelloworld.co.kr/questions/1038 I was trying to answer the question, but I thought it would be nice to share it with you, so I'm moving it here.
java iterator tryhelloworld
Set1.iterator() creates a new iterator every time. The output statement of iter1 == ether2 in the code below is not executed. This is because iter1 and iter2 are newly created emitters. So if you want to use hasNext, you shouldn't use the e-interator that you got from the set1.iterator() every time, but you have to make one as shown below and keep using it.
import java.util.*;
class CodeRunner{
public static void main(String[] args){
Set<String> set1 = new HashSet<>();
set1.add("dada");
set1.add("dsafd");
set1.add("dfds");
Iterator<String> iter1 = set1.iterator();
Iterator<String> iter2 = set1.iterator();
if(iter1==iter2){
System.out.println("SameIterator");
}
while(iter1.hasNext()){
String str = iter1.next();
System.out.println(str);
}
// while(set1.iterator().hasNext(){//set1.iterator() is always true because it is a new iterator.
// // String str = set1.iterator().next();
// // System.out.println(str);
// }
}
}
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