What's the difference between taking a dot (.) and doing ->?

1 .The operator cannot be written in the pointer. 2 foo->bar() = (*foo).bar()

2 must be enclosed in parentheses, such as (*foo). Since the . operator has a higher priority than the * operator, *foo.bar() is likely to cause compilation errors.

In addition, the . operator cannot be overloaded -> can be overloaded, so be careful when writing