void dice(int count) {
int i;
if (n < count) {
print(n);
return;
}
for (i = arr[count - 1]; i <= 6; i++) {
arr[count] = i;
dice(count + 1);
}
}
This is.
Looking at this code, count gave the parameter device(1) in the main function.
What I don't understand from this code is that if i is given as arr(count-1), does i mean that i increases the value by 1 from arr 0 and stores it? I don't understand
for (i = arr[count - 1]; i <= 6; i++) {
Assign the count-1th element of arrr to i and increase i by 1 from the next iteration until 7.
Additional questions are asked, so I am revising my answer:
I didn't understand. I don't quite understand that i initializes to arr[count-1] and increases i. When I do a for statement, I only see the form i=0 or i=num; or i=num-1. You initialize the value of i with an array, but you don't increase i and put it in an array. So when you initialize it with an array, does it mean that the value in i remains unchanged and only the repetition door rotates 6 times?
for (i = arr[count - 1]; i <= 6; i++) {
// a repeating sentence
}
int idx = arr[count - 1];
for (i = idx; i <= 6; i++) {
// a repeating sentence
}
The execution results of the above two codes are the same.
To initialize i to arr[count-1] literally allocates a value in the arr array at arr-1... This is.
Since there is an increasing or decreasing expression i++, of course i increases by 1 at the end of each loop.
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