For example, my list is
list = [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15]
If you say
New list
new_list = [[[0,1] ,[0,2], [0,3],.....,[0,15]], [[1, 2], [1, 3], [1, 4],...[1,15]], [[2, 3],....[2,15]],....[[14,15]]]
I'm going to make a list in the list.
[x, y] If I say x, I want to make sure that the same list is bound to the same list. I want to set y from one larger than x to the last value of 15. The value of y must be greater than x.
sss = [ ]
ttt = [ ]
i = 0
j = 1
while j < len(seq_list):
if j>i:
x = [i,j]
j = j+1
sss.append(x)
if j == len(seq_list):
i = i+1
print(sss)
ttt.append(sss)
j=i+1
All the sets are tied to the sss list. I ask for your help me. <
python
I think you can do it like this.
L = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]
result = []
for i in L[:-1]:
for i2 in range(i+1, L[-1]+1):
result.append([i, i2])
result = result[:-1]
# result value
[
[[0, 1], [0, 2], ... [0, 14], [0, 15]],
[[1, 2], [1, 3], ... [1, 14], [1, 15]],
...
[[13, 14], [13, 15]],
[[14, 15]]
]
Below is a simplified code.
L = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]
result = [[[i, i2] for i2 in range(i+1, L[-1]+1)] for i in L[:-1]]
I hope it was helpful!
Please keep that in mind.
src = [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15]
[[[x, y] for y in src[x+1:]] for x in src[:-1]]
[[[0, 1],
[0, 2],
[0, 3],
[0, 4],
[0, 5],
[0, 6],
[0, 7],
[0, 8],
[0, 9],
[0, 10],
[0, 11],
[0, 12],
[0, 13],
[0, 14],
[0, 15]],
[[1, 2],
[1, 3],
[1, 4],
[1, 5],
[1, 6],
[1, 7],
[1, 8],
[1, 9],
[1, 10],
[1, 11],
[1, 12],
[1, 13],
[1, 14],
[1, 15]],
...
...
[[10, 11], [10, 12], [10, 13], [10, 14], [10, 15]],
[[11, 12], [11, 13], [11, 14], [11, 15]],
[[12, 13], [12, 14], [12, 15]],
[[13, 14], [13, 15]],
[[14, 15]]]
Extra. Try it with scalar
val src = 0 to 15
val r = for(x <- src.slice(0, src.size - 1)) yield for(y <- src.slice(x+1, src.size)) yield (x, y)
r(10).foreach(println)
(10,11)
(10,12)
(10,13)
(10,14)
(10,15)
r(12).foreach(println)
(12,13)
(12,14)
(12,15)
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