Question 1: (Solution)
[Pure Fore] Alice Total Cream 50 ml
[Glossy Blossom] One nail sticker, Vivid Shell
[Apieu] iMousse. [#3 Maple Toast] 6g
I want to erase the brand name first
brand = ["Pure Fore", "Glossy Blossom", "Apieu"]
target.replace("[", "").replace(brand, "").replace("]", "")
If you do this, Apeu disappears at the back, too Is there a way to erase [brand name] using the regular expression? It doesn't have to be a regular expression!
+
print (re.compile('\[A-za-z is-he]+\]').sub('',target))
Number one is working like this.
If there is any other way to do it, please let me know
Question 2:
A
[Apieu] iMousse [No.4_Ginger Cream] 6g
[Apieu] i-mousse [No.5_Daily Mocha] 6g
B
[APIEU] iMUS
[Apieu] I Mousse
Is there a way to make A look like B by leaving only the words that match the beginning and erasing the words in the end?
python regex
I made the brand name based on the fact that it is always located at the top of the line.
"[Brand name] Blah blah"
Code to remove only [] at the beginning of the line.
import re
text ="[Pure Fore] Alice Total Cream 50 ml
[Glossy Blossom] One nail sticker, Vivid Shell
[Apieu] i-mousse. [#3 Maple Toast] 6g'""
print(re.sub('^\[\w+\] ', '', text, flags=re.MULTILINE))
# Output Results
#Alice Total Cream 50 ml
#NailSticker Vivid Shell 1 ea
#Immus [No. 3_Maple Toast] 6 g
Code to find matches from the beginning of a sentence.
In the example you suggested, it would be [Apieu] Imitus [.
difflib library was used. (Default library)
from difflib import SequenceMatcher
string1 = "[Apieu] iMousse [No.4_Ginger Cream] 6g"
string2 = "[Apieu] iMousse [No.5_Daily Mocha] 6g"
match = SequenceMatcher(None, string1, string2).find_longest_match(0, len(string1), 0, len(string2))
print(string1[match.a:match.a+match.size]) # "[Apieu] iMousse []"
The above code was created by referring to here (actually imported).)
I hope it was helpful!
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