I'm a beginner who started Python last night. I know the basics because I did a little bit of C before, but it's a little harder than I thought. First of all, I'm sorry that the title of the question is ambiguous. There was no other way to express it. I was working on a code that took a three-digit number and represented it as a picture. It's my first time making it for practice, so it's a bit messyI'll just upload it.
zero = ["***",
"* *",
"* *",
"* *",
"***"]
one = [" * ",
"** ",
" * ",
" * ",
"***"]
two = ["***",
" *",
"***",
"* ",
"***"]
three = ["***",
" *",
"***",
" *",
"***"]
four = [" *",
" **",
"* *",
"***",
" *"]
five = ["***",
"* ",
"***",
" *",
"***"]
six = ["***",
"* ",
"***",
"* *",
"***"]
seven = ["***",
" *",
" * ",
" * ",
" * "]
eight = ["***",
"* *",
"***",
"* *",
"***"]
nine = ["***",
"* *",
"***",
" *",
"***"]
listup = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
N = 0
def Display(n):
i = 0
ycdn = 0
bufferch = ["","",""]
ln = ["", "", ""]
while i <= 2:
ln[i] = listup[int(n[i])]
i += 1
N = input('Type 3-digit number: ')
str(N)
print(N[0], N[1], N[2])
print('\n\n')
Display(N)
Blocked in Display() function. The method I came up with was,
I wonder how we can replace the values of ln with variables in number 3. Or is there a better way? I'm sorry for the poor explanation.
python
zero= ["***",
"* *",
"* *",
"* *",
"***"]
one = [" * ",
"** ",
" * ",
" * ",
"***"]
two = ["***",
" *",
"***",
"* ",
"***"]
three = ["***",
" *",
"***",
" *",
"***"]
four = [" *",
" **",
"* *",
"***",
" *"]
five = ["***",
"* ",
"***",
" *",
"***"]
six = ["***",
"* ",
"***",
"* *",
"***"]
seven = ["***",
" *",
" * ",
" * ",
" * "]
eight = ["***",
"* *",
"***",
"* *",
"***"]
nine = ["***",
"* *",
"***",
" *",
"***"]
listup = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
N = 0
def Display(n):
buf = ''
buf2 = ['']*5
for i in n:
tmp = 'listup[%d]'%int(i)
buf = eval(tmp)
for idx, j in enumerate(eval(buf)):
buf2[idx] += j
buf2[idx] += ' '
for i in range(0,5):
print(buf2[i])
N = input('Type 3-digit number: ')
str(N)
print(N[0], N[1], N[2])
print('\n')
Display(N)
#result
#Type 3-digit number: 456
#4 5 6
# * *** ***
# ** * *
#* * *** ***
#*** * * *
# * *** ***
You do not need to make listup an array of "variable names".
zero = ["***",
"* *",
"* *",
"* *",
"***"]
one = [" * ",
"** ",
" * ",
" * ",
"***"]
two = ["***",
" *",
"***",
"* ",
"***"]
three = ["***",
" *",
"***",
" *",
"***"]
four = [" *",
" **",
"* *",
"***",
" *"]
five = ["***",
"* ",
"***",
" *",
"***"]
six = ["***",
"* ",
"***",
"* *",
"***"]
seven = ["***",
" *",
" * ",
" * ",
" * "]
eight = ["***",
"* *",
"***",
"* *",
"***"]
nine = ["***",
"* *",
"***",
" *",
"***"]
listup = [zero, one, two, three, four, five, six, seven, eight, nine]
N = 0
def Display(n):
screen = ['', '', '', '', '']
for d in n:
d = int(d)
for i, l in enumerate(listup[d]):
screen[i] += l
screen[i] += ' '
for l in screen:
print(l)
N = input('Type 3-digit number: ')
N = str(N)
print(N)
print('\n\n')
Display(N)
In the end, it's the same thing when you solve it,
Let's put a spoon on the code above.
def Display(n):
for line in zip(*(listup[int(d)] for d in n)):
print(" ".join(line))
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