Hello. I'm implementing a calculator using a stack.
If you enter only integers now, the problem is saved to the list as a string. ex) 1+2/3 [1,+,2,/,3]
But I'm asking you a question because I'm trying to save the mistake.
ex)1.2+3/4 The value I want [1.2,+,3,/,4]
It doesn't come out well even if I google it. I'd appreciate your help.
The part that I'm coding right now is elif token in '.':.
I tried to add the front and the back based on the string when the string . came in. But I don't think that's right, so I'm asking.
class Stack:
def __init__(self):
self.items = []
def push(self, val):
self.items.append(val)
def pop(self):
try:
return self.items.pop()
except IndexError:
print("Stack is empty")
def top(self):
try:
return self.items[-1]
except IndexError:
print("Stack is empty")
def __len__(self):
return len(self.items)
def isEmpty(self):
return self.__len__() == 0
def get_token_list(expr):
opstack = Stack()
outstack = []
token_list = expr
for token in token_list:
print(token)
if token == '(':
opstack.push(token)
elif token == ')':
opstack.push(token)
eliftoken in '+-/*^': pop an operator higher than oneself in #opstack
#while (not opstack.isEmpty()) and \
#(prec[opstack.top()] >= prec[token]):
#outstack.append(opstack.pop())
#print(outstack)
# # print(opstack)
opstack.push(token)
elif token in '.':
outstack.append(opstack.top()+token)
opstack.push(token)
if opstack.pop() == '.': #
outstack.append(opstack.pop()+opstack.top()+token)
opstack.push(token)
#outstack.append(opstack.top())
#if outstack in '.':
# # outstack.append(str(opstack.pop()+'.'+opstack.pop()))
outstack.append(opstack.pop())
return print(outstack)
expr = input()
value = get_token_list(expr)
#value = compute_postfix(infix_to_postfix(get_token_list(expr)))
#print(value)
Can I know how you solved it? I'd like to see some coding ㅠ<
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