I want to find the index of the value entered in n in the puzzle list below, but after 1, 2, 3, and 4 in the first list, the error keeps occurring. index = puzzle[i].index(n) This part seems strange, but I don't know how to fix it.
And if I can't find it, I want to return the return value None, and if I find it, I want to return the index value, what should I do?
puzzle= [[1,2,3,4], [5,6,7,8], [9,10,11,12], [13,14,15,16]]
def get_index(puzzle, n):
for i in range(len(puzzle)):
index = puzzle[i].index(n)
return index
get_index(puzzle, 3)
puzzle = [[1,2,3,4],[5,6,7,8],[9,10,11,12],[13,14,15,16]]
def get_index(puzzle, n):
for idx1, i in enumerate(puzzle):
for idx2, j in enumerate(i):
if j == n:
return idx1, idx2
return None
get_index(puzzle, 10)
#(2, 1)
get_index(puzzle, 100)
#None
There are many ways, so I think the answer is to do what you think
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That's a pretty good code. It's not that hard. The index found in the current state function isn't actually the answer, but it's the second index of the two-dimensional index you're looking for.
What is the first index? It's i. So, if you find it, you can return (i, index).
The big problem right now is that I'm good at finding things in the first row like 3, but things like 7 are error-prone.
This is an error that occurs because 7 does not exist in the first line (i.e., puzzle[0]). This is an error that can be avoided by checking the if in puzzle[i] condition in advance.
OK?
puzzle = [[1,2,3,4],[5,6,7,8],[9,10,11,12],[3,14,15,16]]
def get_index(puzzle, n):
indice = []
for i, puz in enumerate(puzzle):
if n in puz:
indice.append(i)
return indice
get_index(puzzle, 3) # [0, 3]
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