To calculate the number of times that occurred before the number of entries occurred

Blockquote

**Enter any integer greater than or equal to 30:

The number of times 0 occurred is 955.

The number of times 1 has occurred is 966.

. . .

The number of times 31 (number of inputs) occurred is 1000 times

The total number of iterations from 0 to the number 31 you enter occurs 1000 times is ~~.**

Blockquote

The results should come out like this, but I don't know how to plan it <

And

unum=int(input("30 or more of the desired integer):"))

array=list(range(0,unum+1))

When

while((array[unum]-unum)!=1000): I don't know what this means <