aList = [1, 2, [1 ,2], 'c', [1, 2] ]
I know that the set function removes duplicate values from the list
Nested list, and if it's a mixed list of characters
When using the set function, an error was printed as unsashable. I was wondering if I could solve the problem by converting the list into a tuple I'm thinking of changing the list to a tuple, using the set function, and then changing it to the original form I'm trying.
list(set([tuple(set(item)) for item in aList]))
I have a question because there is an error that 'int' object is not usable.
python set list-comprehension
The list is a changeable type, so it cannot be used as a hash.
Try it with the following.
set(tuple(i) if type(i) == list else i for i in aList)
If the item is 1, an error will occur in the set.
It's too long. I don't know if you intended this, but....
[list(x) if isinstance(x, tuple) else x for x in set([tuple(i) if isinstance(i, list) else i for i in aList ])]
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