#include <stdio.h>
int main(void)
{
int num1, num2;
char arithmetic;
printf ("Please enter 2 numbers and an operator."\n\n");
printf ("Operators are as follows:\n");
printf("plus:+, subtract:-, multiply:*, divide:/\n");
printf ("Input Order: Integer 1 Operator Integer 2\n\n");
scanf_s("%d %c %d", &num1, &arithmetic, &num2, sizeof(num1), sizeof(arithmetic), sizeof(num2));
switch(arithmetic)
{
case'+':
printf("%d %c %d = %d\n", num1, arithmetic, num2, num1 +num2);
break;
case'-':
printf("%d %c %d = %d\n", num1, arithmetic, num2, num1 -num2);
break;
case'*':
printf("%d %c %d = %d\n", num1, arithmetic, num2, num1 *num2);
break;
case'/':
printf("%d %c %d = %d\n", num1, arithmetic, num2, (float)num1 /num2);
break;
default:
printf("Invalid operator entered.\n");
break;
}
return 0;
}
I made it with but I can't print out the switch-case statement in the back... What's the problem?
c++
Wrong place 1
scanf_s("%d %c %d", &num1, &arithmetic, &num2, sizeof(num1), sizeof(arithmetic), sizeof(num2));
It should be done as below.
scanf_s("%d %c %d", &num1, &arithmetic, sizeof(arithmetic), &num2);
Wrong place 2
printf("%d %c %d = %d\n", num1, arithmetic, num2, (float)num1 / num2);
It should be done as below.
printf("%d %c %d = %f\n", num1, arithmetic, num2, (float)num1 / num2);
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