I want to put None=0 in Python.

Is it like this?

def Add(x,y):
    return(x if x else0)+(y if y else0)


print(Add(10,1))#11
print(Add(10, None))#10
print(Add(None,1))#1
print(Add(None, None))#0

Python should not be able to do it.

The
• + operator runs __add__ on the left or _radd__ on the right
For
• 1+None, both sides are int and NoneType
• These types (classes) are built-in and cannot be changed to _add__
etc.
• Therefore, you cannot change the behavior of + in this expression

Once you have your own type, you can change the behavior of + for that type.

Example:

class N(int):

    def__add__(self, other):
        if other==None:
            other = 0
        return N(super().__add__(other))

    def__radd__(self, other):
        return self.__add__(other)

n0 = N(0)
n1 = N(1)
n2 = N(2)

print(f"{n1+None=}")#1
print(f"{None+n1=}")#1
print(f"{n1+2=}")#3
print(f"{1+n2=}")#3
print(f"{n1+n2=}")#3
print(f"{n0+1+None=}")#1

If you want to complete it properly, you need to define other methods to emulate the numeric type.SymPy and others are such approaches.

There is no way to avoid the unsupported operand type(s) for +: 'int' and 'NoneType' exception when using the + operator for None, and it will require some redundancy like the other answers.
By the way, there is also a way to get 0 using the or operator, such as None or 0.

x,y=1,None
Returns print((x or 0)+(y or 0))#1